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author | Stephen Warren <swarren@nvidia.com> | 2016-01-29 16:10:04 -0700 |
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committer | Simon Glass <sjg@chromium.org> | 2016-02-09 15:41:19 -0700 |
commit | 986fe378172fa4bd5be1432ab2f8f7c2b1c43bae (patch) | |
tree | 643948b0e7d77d99ae113978bf435623bd92af1e /test/py | |
parent | 1934665742e38c8ced9342a9c3005a3eab0b1a7c (diff) | |
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itest: allow map_physmem to return 0 in limited cases
On some systems, RAM starts at address 0. If the user executes itest
against address 0 on such a system, it will call map_physmem(0, ...)
which will return 0 back; mapping only changes the address on sandbox.
This causes itest to believe map_physmem() has failed, and hence fails
the comparison.
Fix itest so that it allows map_physmem() to return 0 /if/ the orignal
address passed to it was also 0.
This fixes "tegra-uboot-flasher flash" on Tegra20.
This has the disadvantage that on sandbox, failed mapping attempts for
address 0 are not detected. Instead, should the code only call
map_physmem() on sandbox? Or, should map_physmem() return its error status
some other way. Or, should the special case only be allowed on systems
where the base of RAM is 0 somehow?
Fixes: 7861204c9af7 ("itest: make memory access work under sandbox")
Signed-off-by: Stephen Warren <swarren@nvidia.com>
Diffstat (limited to 'test/py')
0 files changed, 0 insertions, 0 deletions