drivers/rtc : move rtc drivers to drivers/rtc

Signed-off-by: Jean-Christophe PLAGNIOL-VILLARD <plagnioj@jcrosoft.com>

1 files changed, 0 insertions, 156 deletions

diff --git a/rtc/date.c b/rtc/date.c
deleted file mode 100644
index a83a723..0000000
--- a/rtc/date.c
+++ /dev/null
@@ -1,156 +0,0 @@
-/*
- * (C) Copyright 2001
- * Wolfgang Denk, DENX Software Engineering, wd@denx.de.
- *
- * See file CREDITS for list of people who contributed to this
- * project.
- *
- * This program is free software; you can redistribute it and/or
- * modify it under the terms of the GNU General Public License as
- * published by the Free Software Foundation; either version 2 of
- * the License, or (at your option) any later version.
- *
- * This program is distributed in the hope that it will be useful,
- * but WITHOUT ANY WARRANTY; without even the implied warranty of
- * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
- * GNU General Public License for more details.
- *
- * You should have received a copy of the GNU General Public License
- * along with this program; if not, write to the Free Software
- * Foundation, Inc., 59 Temple Place, Suite 330, Boston,
- * MA 02111-1307 USA
- */
-
-/*
- * Date & Time support for Philips PCF8563 RTC
- */
-
-#include <common.h>
-#include <command.h>
-#include <rtc.h>
-
-#if defined(CONFIG_CMD_DATE) || defined(CONFIG_TIMESTAMP)
-
-#define FEBRUARY		2
-#define	STARTOFTIME		1970
-#define SECDAY			86400L
-#define SECYR			(SECDAY * 365)
-#define	leapyear(year)		((year) % 4 == 0)
-#define	days_in_year(a) 	(leapyear(a) ? 366 : 365)
-#define	days_in_month(a) 	(month_days[(a) - 1])
-
-static int month_days[12] = {
-	31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
-};
-
-/*
- * This only works for the Gregorian calendar - i.e. after 1752 (in the UK)
- */
-void GregorianDay(struct rtc_time * tm)
-{
-	int leapsToDate;
-	int lastYear;
-	int day;
-	int MonthOffset[] = { 0,31,59,90,120,151,181,212,243,273,304,334 };
-
-	lastYear=tm->tm_year-1;
-
-	/*
-	 * Number of leap corrections to apply up to end of last year
-	 */
-	leapsToDate = lastYear/4 - lastYear/100 + lastYear/400;
-
-	/*
-	 * This year is a leap year if it is divisible by 4 except when it is
-	 * divisible by 100 unless it is divisible by 400
-	 *
-	 * e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 will be
-	 */
-	if((tm->tm_year%4==0) &&
-	   ((tm->tm_year%100!=0) || (tm->tm_year%400==0)) &&
-	   (tm->tm_mon>2)) {
-		/*
-		 * We are past Feb. 29 in a leap year
-		 */
-		day=1;
-	} else {
-		day=0;
-	}
-
-	day += lastYear*365 + leapsToDate + MonthOffset[tm->tm_mon-1] + tm->tm_mday;
-
-	tm->tm_wday=day%7;
-}
-
-void to_tm(int tim, struct rtc_time * tm)
-{
-	register int    i;
-	register long   hms, day;
-
-	day = tim / SECDAY;
-	hms = tim % SECDAY;
-
-	/* Hours, minutes, seconds are easy */
-	tm->tm_hour = hms / 3600;
-	tm->tm_min = (hms % 3600) / 60;
-	tm->tm_sec = (hms % 3600) % 60;
-
-	/* Number of years in days */
-	for (i = STARTOFTIME; day >= days_in_year(i); i++) {
-		day -= days_in_year(i);
-	}
-	tm->tm_year = i;
-
-	/* Number of months in days left */
-	if (leapyear(tm->tm_year)) {
-		days_in_month(FEBRUARY) = 29;
-	}
-	for (i = 1; day >= days_in_month(i); i++) {
-		day -= days_in_month(i);
-	}
-	days_in_month(FEBRUARY) = 28;
-	tm->tm_mon = i;
-
-	/* Days are what is left over (+1) from all that. */
-	tm->tm_mday = day + 1;
-
-	/*
-	 * Determine the day of week
-	 */
-	GregorianDay(tm);
-}
-
-/* Converts Gregorian date to seconds since 1970-01-01 00:00:00.
- * Assumes input in normal date format, i.e. 1980-12-31 23:59:59
- * => year=1980, mon=12, day=31, hour=23, min=59, sec=59.
- *
- * [For the Julian calendar (which was used in Russia before 1917,
- * Britain & colonies before 1752, anywhere else before 1582,
- * and is still in use by some communities) leave out the
- * -year/100+year/400 terms, and add 10.]
- *
- * This algorithm was first published by Gauss (I think).
- *
- * WARNING: this function will overflow on 2106-02-07 06:28:16 on
- * machines were long is 32-bit! (However, as time_t is signed, we
- * will already get problems at other places on 2038-01-19 03:14:08)
- */
-unsigned long
-mktime (unsigned int year, unsigned int mon,
-	unsigned int day, unsigned int hour,
-	unsigned int min, unsigned int sec)
-{
-	if (0 >= (int) (mon -= 2)) {	/* 1..12 -> 11,12,1..10 */
-		mon += 12;		/* Puts Feb last since it has leap day */
-		year -= 1;
-	}
-
-	return (((
-		(unsigned long) (year/4 - year/100 + year/400 + 367*mon/12 + day) +
-			year*365 - 719499
-	    )*24 + hour /* now have hours */
-	  )*60 + min /* now have minutes */
-	)*60 + sec; /* finally seconds */
-}
-
-#endif